A bar carries axial tension of 50 MPa and bending stress of 80 MPa. What is the maximum normal stress?
- A30 MPa
- B50 MPa
- C80 MPa
- D130 MPaCorrect
Solution
Concept
Superposition of combined axial tension and bending stresses
Formula
σmax = σaxial + σbending
Step-by-step solution
1. When a prismatic bar carries simultaneous axial tension and bending, total normal stress is obtained by superposition. 2. Given axial tensile stress σaxial = 50 MPa (uniform tension across section). 3. Given maximum bending stress σbending = 80 MPa (tensile at extreme tension fiber, compressive at opposite fiber). 4. The maximum normal stress occurs at the extreme tension fiber: σmax = σaxial + σbending = 50 + 80 = 130 MPa. Answer: D
Explanation
When a structural member is subjected to simultaneous axial tension and bending, the maximum normal stress occurs at the extreme tensile fiber where axial tensile stress and bending tensile stress act in the same direction: σmax = σaxial + σbending = 50 MPa + 80 MPa = 130 MPa.
Why the other options are wrong
A) 30 MPa is the minimum net stress at the extreme compressive fiber (80 - 50). B) 50 MPa is axial stress alone. C) 80 MPa is bending stress alone.
Shortcut
Combined stress = Axial tension + Bending stress = 50 + 80 = 130 MPa.
Common mistake
Subtracting bending stress from axial tension (80 - 50 = 30 MPa), which gives minimum stress instead of maximum.
Correct answer: D) 130 MPa