A single degree of freedom system has mass m = 2 kg and stiffness k = 200 N/m. The natural frequency in Hz is
- A0.8 Hz
- B1.6 HzCorrect
- C15.9 Hz
- D31.8 Hz
Solution
Concept
SDOF undamped natural frequency calculation
Formula
fn = (1 / (2·π)) × √(k / m)
Step-by-step solution
1. Given mass m = 2 kg and stiffness k = 200 N/m. 2. Undamped circular frequency ωn = √(k / m) = √(200 / 2) = √(100) = 10 rad/s. 3. Cyclic natural frequency in Hertz fn = ωn / (2 × π). 4. fn = 10 / (2 × 3.14159) = 10 / 6.2832 = 1.592 Hz approx 1.6 Hz. Answer: B
Explanation
The circular natural frequency of a single-degree-of-freedom system is ωn = √(k/m) = √(200/2) = 10 rad/s. Dividing by 2·π converts this to cyclic frequency fn = 10 / (2×3.1416) = 1.59 Hz, which rounds to 1.6 Hz.
Why the other options are wrong
A) 0.8 Hz results from incorrectly dividing 10 by 4·π. C) 15.9 Hz is off by a factor of 10 from arithmetic error. D) 31.8 Hz is off by a factor of 20.
Shortcut
f = (1 / 2π) × √(k/m) = 10 / 6.28 ≈ 1.6 Hz.
Common mistake
Reporting circular frequency ω = 10 rad/s instead of dividing by 2·π to obtain cyclic frequency in Hz.
Correct answer: B) 1.6 Hz