A structural steel component (yield stress = 300 MPa) is subjected to the following principal stresses under plane stress conditions: σ1 = 180 MPa (tensile) σ2 = −80 MPa (compressive) σ3 = 0 MPa Using the Maximum Shear Stress Theory, determine the safety condition of the component.
- ASafeCorrect
- BMarginal
- CFailing
- DCannot be determined
Solution
Concept
Tresca theory safety check under biaxial tension compression
Formula
σ1 - σ2 ≤ σy
Step-by-step solution
1. The principal stresses in plane stress are: σ1 = 180 MPa, σ2 = -80 MPa, and σ3 = 0 MPa. 2. Under Maximum Shear Stress Theory (Tresca), yielding occurs when max(|σi - σj|) ≥ σy. 3. The three stress differences are: |180 - (-80)| = 260 MPa; |-80 - 0| = 80 MPa; |0 - 180| = 180 MPa. 4. The maximum stress difference is 260 MPa, which is strictly less than the yield strength of 300 MPa. 5. Therefore, the component is Safe (FOS = 300 / 260 = 1.15). Answer: A
Explanation
Under plane stress with principal stresses σ1 = 180 MPa, σ2 = -80 MPa, and σ3 = 0, the maximum stress difference is |σ1 - σ2| = 180 - (-80) = 260 MPa. According to the Maximum Shear Stress Theory, yielding occurs when this difference equals the yield stress (300 MPa). Because 260 MPa < 300 MPa, the component is safe.
Why the other options are wrong
B) Marginal is undefined in deterministic factor-of-safety criteria. C) Failing is incorrect because 260 MPa does not exceed the 300 MPa yield threshold. D) Principal stresses and yield limit provide complete determinacy.
Shortcut
Max stress difference = 180 - (-80) = 260 MPa < 300 MPa (Yield strength) => Safe.
Common mistake
Comparing only the maximum tensile stress (180 MPa) and ignoring the tensile-compressive stress span.
Correct answer: A) Safe