A symmetrical right–circular cone of wood, floats in fresh water with axis vertical and the apex downmost. The axial height of the cone is (H). The submerged portion has a height (h) measured upwards from the apex. What would be the height of the centre of buoyancy from apex?
- Ah/2
- B5h/8
- C2h/3
- D3h/4Correct
Solution
Concept
Centre of buoyancy = centroid of the displaced volume
Formula
Centroid of a cone from its apex = 3/4 × height
Step-by-step solution
1. The displaced liquid has the shape of a cone of height h with its apex at the bottom (apex of the floating cone). 2. The centroid of a solid cone lies at 3/4 of its height from the apex. 3. So the centre of buoyancy is 3h/4 above the apex.
Explanation
The centre of buoyancy is the centroid of the volume of liquid displaced. The submerged part of the cone is itself a cone with height h, so its centroid is 3h/4 from the apex (h/4 from the base).
Shortcut
Solid cone centroid: h/4 from base. Triangle centroid: h/3 from base. Hemisphere: 3R/8 from base.
Common mistake
Using 2h/3 (centroid of a triangular area) instead of 3h/4 (solid cone).

Correct answer: D) 3h/4