For a semicircular plate of diameter 'D' and radius 'R', with 'y' as the vertical axis passing through the diameter and 'x' as the horizontal axis passing through the diameter, the moment of inertia about the y axis will be:
- AπD⁴ / 128Correct
- B0.10976 R³
- CπD⁴ / 16
- D0.10976 R⁴
Solution
Concept
For a semicircle, MOI about the diameter and about the symmetry axis through the centre are both half of the full circle value.
Formula
Ifull circle = πD4/64; Isemicircle = πD4/128 = πR4/8
Step-by-step solution
1. For a full circle, MOI about any diameter = πD4/64. 2. A semicircle is half of the circle, and both axes pass through the centre of the diameter. 3. So Iy = (1/2) × πD4/64 = πD4/128. 4. In terms of R: πR4/8 ≈ 0.393 R4. 5. Answer: πD4/128.
Explanation
The y axis passes through the centre of the diameter, so the semicircle is exactly half of a circle about this axis. Half of πD4/64 gives πD4/128. The value 0.10976 R4 is used only for the centroidal axis parallel to the diameter.
Why the other options are wrong
B: R3 has the wrong unit for MOI. C: πD4/16 is too large and is not a standard result for a semicircle. D: 0.10976 R4 is the MOI about the centroidal axis parallel to the diameter, not about the y axis.
Shortcut
For a semicircle, MOI about the diameter or the symmetry axis through the centre = half of the circle value = πD4/128.
Common mistake
Choosing 0.10976 R4, which is the centroidal value parallel to the diameter, not the value about the given axis.
Correct answer: A) πD⁴ / 128