If V sb is the factored shear force, T b is the factored tensile force, V db is the design shear force and T db is the design tensile force, then the design requirement of bolted connection subjected to direct shear and axial tension is
- A(Vsb/Vdb)² + (Tb/Tdb)² ≤ 1.0Correct
- B(Vdb/Vsb)² + (Tdb/Tb)² ≤ 1.0
- CVsb/Vdb + Tb/Tdb ≤ 1.0
- DVdb/Vsb + Tdb/Tb ≤ 1.0
Solution
Concept
Interaction of shear and tension (IS 800 cl. 10.3.6)
Formula
(Vsb/Vdb)² + (Tb/Tdb)² ≤ 1
Step-by-step solution
1. IS 800:2007 uses a quadratic interaction between the factored and design values. 2. The sum of squares of the ratios must not exceed 1.0.
Explanation
Demand over capacity ratios must be used, with squares in the 2007 code.
Why the other options are wrong
B and D invert the ratios; C is the linear form of the older code.
Shortcut
Demand/capacity, squared.
Common mistake
Using the linear form.
Correct answer: A) (Vsb/Vdb)² + (Tb/Tdb)² ≤ 1.0