In a signal design as per the Indian Road Congress specifications, if the sum of the ratios of normal flows to saturation flows of two directional traffic flows is 0.50 and the total lost time per cycle is 20s, then the optimum cycle length in seconds is
- A50
- B70Correct
- C90
- D110
Solution
Concept
Webster's Optimum Signal Cycle Length
Formula
C0 = (1.5L + 5) / (1 - Y)
Step-by-step solution
1. Identify given parameters: Total lost time (L) = 20 s and critical flow ratio sum (Y) = 0.50 2. Calculate the numerator: (1.5 \* 20) + 5 = 35 3. Calculate the denominator: 1 - 0.50 = 0.50 4. Divide numerator by denominator: 35 / 0.50 = 70 seconds
Explanation
According to Webster's formula, the optimum signal cycle length is given by C0 = (1.5L + 5) / (1 - Y), where L is the total lost time and Y is the sum of the flow ratios. Substituting the given values: C0 = (1.5 × 20 + 5) / (1 - 0.50) = (30 + 5) / 0.50 = 35 / 0.50 = 70 seconds. Therefore, option B (70) is correct.
Common mistake
Students often forget to add 5 in the numerator of Webster's formula, calculating C0 = (1.5L) / (1 - Y) = (1.5 × 20) / 0.50 = 60/0.50 = 60, or incorrectly forgetting the (1 - Y) term in the denominator and calculating C0 = 1.5L + 5 = 35 seconds.

Correct answer: B) 70