In a T-section (flange width 400 mm, flange thickness 100 mm, web depth 500 mm, web width 100 mm, overall depth 600 mm). The distance of the geometrical neutral axis and the plastic neutral axis from the top fibre will be ______ respectively.
- A300 mm and 150 mm
- B217 mm and 150 mmCorrect
- C300 mm and 100 mm
- D100 mm and 217 mm
Solution
Concept
The geometrical neutral axis passes through the centroid of the cross-section, whereas the plastic neutral axis divides the total area of the cross-section into two equal halves.
Formula
ybar = (A1·y1 + A2·y2) / (A1 + A2)
Step-by-step solution
1. Understand the T-section dimensions: Flange width bf = 400 mm, Flange thickness tf = 100 mm, Web width bw = 100 mm, Overall depth D = 600 mm, Web depth dw = 500 mm. 2. Calculate the total area (A) and centroid (GNA) from the top fiber: Area of flange (Af) = 400 × 100 = 40,000 mm² Area of web (Aw) = 100 × 500 = 50,000 mm² Total Area = 90,000 mm² Centroid from top fibre (ybar) = [(40000 × 50) + (50000 × (100 + 250))] / 90000 = [2,000,000 + 17,500,000] / 90000 = 19,500,000 / 90000 = 216.67 mm ≈ 217 mm. 3. Calculate the Plastic Neutral Axis (PNA): Total Area / 2 = 90,000 / 2 = 45,000 mm². Area of the flange = 40,000 mm² (which is less than 45,000 mm²). Therefore, PNA lies within the web, just below the flange. Let yp be the depth of PNA from the top fiber. Area of flange + Area of web portion up to PNA = 45,000 mm² 40,000 + bw × (yp - tf) = 45,000 40,000 + 100 × (yp - 100) = 45,000 100 × (yp - 100) = 5,000 yp - 100 = 50 yp = 150 mm.
Explanation
Correct answer: B) 217 mm and 150 mm
