Q.47 The maximum shear stress (in N/mm²) in a reinforced concrete beam of M-25 grade as per IS 456-2000 is given as:
- A3.4
- B3.1Correct
- C3.5
- D2.8
Solution
Concept
IS 456-2000 limits the nominal shear stress τv in a beam to τc,max, which depends on concrete grade.
Formula
τv = Vu / (b × d) ≤ τc,max
Step-by-step solution
1. Open IS 456-2000, Table 20: maximum shear stress τc,max for limit state design. 2. Values are M20 = 2.8, M25 = 3.1, M30 = 3.5, M35 = 3.7, M40 and above = 4.0 N/mm². 3. For M25, τc,max = 3.1 N/mm². 4. So the answer is (B).
Explanation
IS 456 gives an upper limit on shear stress in beams for each concrete grade. For M25 this limit is 3.1 N/mm². If τv is more than this value, the section must be redesigned, because stirrups alone cannot help.
Why the other options are wrong
A (3.4): not a value in the table. C (3.5): this is for M30. D (2.8): this is for M20.
Shortcut
Remember the series 2.8, 3.1, 3.5, 3.7, 4.0 for M20 to M40.
Common mistake
Mixing up grades (2.8 is for M20, 3.5 is for M30), or using the working stress table values instead of the limit state values.
Correct answer: B) 3.1