The free mean speed of a road is 70 kmph. At jam conditions, the average spacing between the vehicles is 6.5 m. What is the maximum flow in vehicles/hour/per lane?
- A2693Correct
- B3591
- C4550
- D5385
Solution
Concept
Calculation of maximum traffic flow capacity
Formula
qmax = (vf × kj) / 4, where kj = 1000 / s
Step-by-step solution
1. Jam density kj = 1000 / average spacing = 1000 / 6.5 = 153.85 vehicles/km. 2. Free mean speed vf = 70 kmph. 3. Maximum flow qmax = (vf × kj) / 4 = (70 × 153.85) / 4 = 2692.3 vehicles/hour/lane. Answer: A
Explanation
Jam density is computed as 1000 divided by the vehicle spacing of 6.5 m, which equals approximately 153.85 vehicles per kilometer. According to Greenshields model, maximum flow occurs at half the free mean speed and half the jam density. Multiplying 35 kmph by 76.92 vehicles per km yields a maximum flow of approximately 2693 vehicles per hour per lane, making option A correct.
Why the other options are wrong
NONE
Shortcut
Maximum traffic flow capacity qmax = (Vf × kj) / 4, where jam density kj = 1000 / average spacing.
Common mistake
Selecting option D or C by using q = Vf × kj directly instead of dividing by 4 to calculate maximum flow capacity.
Correct answer: A) 2693