The shear stress at the neutral axis in a beam of rectangular section with width is equal to 25 mm and effective depth 50 mm subjected to shear force of 5 kN is
- A5 MPa
- B6 MPaCorrect
- C10 MPa
- D15 MPa
Solution
Concept
Maximum Shear Stress in Rectangular Section
Formula
τmax = 1.5 × (V / A) = 3V / (2 × b × d)
Step-by-step solution
1. Calculate cross-sectional area: A = b × d = 25 mm × 50 mm = 1250 mm² 2. Calculate average shear stress: τ\_avg = V / A = 5000 N / 1250 mm² = 4 MPa 3. Calculate maximum shear stress at neutral axis: τ\_max = 1.5 × τ\_avg = 1.5 × 4 MPa = 6 MPa
Explanation
For a rectangular beam, maximum shear stress occurs at the neutral axis and is equal to 1.5 times the average shear stress. First, calculate the average shear stress by dividing the shear force (5,000 N) by the cross-sectional area (25 mm × 50 mm = 1,250 mm²), which equals 4 MPa. Multiplying 4 MPa by 1.5 gives 6 MPa.
Shortcut
Use the formula τmax = 1.5 × (V / A). Quickly calculate average stress (V / A) as 5,000 N / 1,250 mm² = 4 MPa, then multiply by 1.5 to get 6 MPa.
Common mistake
Students often mistake maximum shear stress for average shear stress by calculating V/A (5000 N / 1250 mm² = 4 MPa) or forget the 1.5 factor for rectangular sections, leading them to select incorrect options or misuse unit conversions.

Correct answer: B) 6 MPa