Three-hinged symmetrical parabolic arch of span 12 m and rise 2 m carries a uniformly distributed load of 1 kN/m for the whole span. The bending moment at the quarter point is
- A15 kNm
- B10.5 kNm
- C6 kNm
- D0Correct
Solution
Concept
Bending Moment in Three-Hinged Parabolic Arch
Formula
Horizontal Thrust: H = (w × L²) / (8 × h) Bending Moment: Mx = Mbeam - H × y = 0 Arch Profile: y = 4 × h × x × (L - x) / L²
Step-by-step solution
1. Identify given values: w = 1 kN/m, L = 12 m, h = 2 m. 2. Recall that for a three-hinged parabolic arch under a uniform UDL over the full span, the beam moment matches the moment from horizontal thrust (M\_beam = H \* y). 3. Calculate net bending moment (Mx = M\_beam - H \* y = 0), which is zero at all points including the quarter point.
Explanation
When a three-hinged parabolic arch carries a uniformly distributed load over its entire span, the shape of the arch matches the shape of the bending moment diagram. Because of this, the moment created by the horizontal thrust at any point cancels out the moment caused by the load, resulting in a net bending moment of zero throughout the entire arch, including at the quarter point.
Shortcut
Remember: A 3-hinged parabolic arch loaded with UDL over the ENTIRE span has ZERO bending moment everywhere. So, no matter what values of span, rise, or UDL are given, the bending moment at any section (including the quarter point) is always 0.
Common mistake
Students often calculate only the simply supported beam bending moment (such as w·L2/24 = 6 kNm) and select Option C, forgetting that in a 3-hinged parabolic arch under full UDL, the moment caused by horizontal thrust (H·y) completely cancels out the beam moment, making the net bending moment zero everywhere.

Correct answer: D) 0