An angle ISA 75×75×6 is connected to a 5 mm thick gusset plate with the 16 mm diameter bolts. If the hole diameter is 16 mm and the allowable bearing stress is 250 MPa, then the bearing strength of bolt will be
- A8 kN
- B20 kNCorrect
- C24 kN
- D50 kN
Solution
Concept
Bearing strength of a bolted connection depends on the bolt diameter, thickness of the connected member (or gusset plate), and the bearing stress.
Formula
Pb = d × t × fp
Step-by-step solution
1. Identify the given parameters: Bolt diameter (d) = 16 mm, Thickness of gusset plate = 5 mm, Thickness of angle leg = 6 mm. 2. Determine the critical thickness (t) for bearing: minimum of gusset plate and angle leg thickness = min(5 mm, 6 mm) = 5 mm. 3. Identify the allowable bearing stress (fp) = 250 MPa (or N/mm²). 4. Calculate the bearing strength: Pb = d × t × fp = 16 mm × 5 mm × 250 N/mm² = 20,000 N = 20 kN.
Explanation
According to IS 800:2007, the bearing strength of a bolt is given by Vpb = 2.5 × d × t × fu / γmb. However, when specific allowable bearing stress is given instead of ultimate tensile stress, bearing strength is calculated as Pb = d × t × σpb. Here, d = 16 mm, t = min(plate thickness, angle thickness) = min(5 mm, 6 mm) = 5 mm, and allowable bearing stress = 250 MPa.
Why the other options are wrong
A: Calculation error or incorrect area. C: Incorrect thickness or stress multiplication. D: Arithmetical error in standard formula.
Shortcut
Remember that bearing strength is projected area (d × t) multiplied by the bearing stress.
Common mistake
Taking the thickness of the angle leg (6 mm) instead of the gusset plate (5 mm) when checking bearing on the gusset plate, or vice versa if checking the angle.
Correct answer: B) 20 kN