For a purely cohesive soil (clay), the angle of internal friction (ϕ) is
- A0°Correct
- B30°
- C45°
- D90°
Solution
Concept
Angle of internal friction for purely cohesive soils
Formula
τ = cu
Step-by-step solution
1. Purely cohesive soils (such as saturated clays under undrained conditions) exhibit constant shear strength. 2. The undrained shear strength equation is τ = cu + σ × tan(φu). 3. Under undrained conditions, undrained angle of internal friction φu = 0°. 4. The failure envelope is a horizontal line parallel to the normal stress axis. Answer: A
Explanation
For a purely cohesive soil (such as saturated clay under undrained conditions, φu = 0), the shear strength envelope is horizontal. The shear strength is entirely derived from undrained cohesion (cu), and the angle of internal shearing resistance (φ) is 0°.
Why the other options are wrong
B) 30° is typical for sands or normally consolidated clays under drained effective stress conditions. C) 45° is common for dense interlocking angular sands. D) 90° is physically impossible for internal friction angles.
Shortcut
Purely cohesive clay (undrained) = φ = 0°; failure envelope is horizontal (τ = cu).
Common mistake
Mistaking the friction angle of clay in drained conditions (φ') with the purely cohesive φu = 0 condition.
Correct answer: A) 0°