Two tanks are connected in parallel by two pipes A and B of identical friction factors and lengths. If the size of pipe A is double than that of pipe B, then their discharges will be in the ratio of
- A2
- B4
- C5.66Correct
- D32
Solution
Concept
Discharge in parallel pipes
Formula
Q ∝ D2.5
Step-by-step solution
1. Same head loss, same f and L: Q ∝ D5/2. 2. QA/QB = 22.5 = 5.66.
Explanation
With identical heads, discharge varies as D2.5.
Why the other options are wrong
4 would apply for D² (equal velocity), and 32 for D⁵.
Shortcut
Parallel: Q ∝ D2.5.
Common mistake
Taking Q ∝ D².
Correct answer: C) 5.66