When two mutually perpendicular principal stresses are unequal but alike, then the maximum shear stress is represented by
- ADiameter of a Mohr’s circle
- BHalf the diameter of a Mohr’s circleCorrect
- COne-third the diameter of a Mohr’s circle
- DOne-fourth the diameter of a Mohr’s circle
Solution
Concept
Maximum shear stress from Mohr's circle
Formula
τmax = (σ1 − σ2)/2 = radius of the Mohr circle
Step-by-step solution
1. Two unequal like principal stresses σ1 and σ2 give a Mohr's circle with diameter (σ1 − σ2). 2. The maximum shear stress equals the radius, i.e. half the diameter.
Explanation
The top point of the Mohr circle gives the maximum shear stress. This is the radius, which is half the diameter of the circle, (σ1 − σ2)/2.
Shortcut
τmax = radius of the Mohr circle.
Common mistake
Taking the diameter as τmax.
Correct answer: B) Half the diameter of a Mohr’s circle