Find the discharge of water flowing over a rectangular notch of length 1 m when the constant head over the notch is 100 mm. Take Cd = 0.60, Given √(2g) = 4.43.
- A52.8 litres/sec
- B48.5 litres/sec
- C56.8 litres/secCorrect
- D62 litres/sec
Solution
Concept
Discharge over a rectangular notch is Q = (2/3) Cd L √(2g) H3/2.
Formula
Q = (2/3) × Cd × L × √(2g) × H3/2
Step-by-step solution
1. Data: L = 1 m, H = 100 mm = 0.1 m, Cd = 0.60, √(2g) = 4.43. 2. H3/2 = 0.11.5 = 0.03162. 3. Q = (2/3) × 0.60 × 1 × 4.43 × 0.03162. 4. (2/3) × 0.60 = 0.4, and 0.4 × 4.43 = 1.772. 5. Q = 1.772 × 0.03162 = 0.0560 m³/s. 6. Q = 0.0560 × 1000 = about 56.0 litres/sec. The nearest option is 56.8 litres/sec (C).
Explanation
For a rectangular notch, discharge depends on H3/2. Putting in the values gives about 0.056 m³/s, which is 56 litres per second. The closest option is C.
Why the other options are wrong
A: 52.8 L/s is too low and does not match the formula. B: 48.5 L/s is too low. It may come from a wrong value of H3/2. D: 62 L/s is too high. It may come from using Cd or √(2g) wrongly.
Shortcut
(2/3) × 0.6 = 0.4, so Q = 0.4 × 4.43 × L × H1.5.
Common mistake
Using H in mm instead of m, or using H2 or H instead of H3/2.
Correct answer: C) 56.8 litres/sec